cubegao

Swift.树中两个节点的最低公共祖先

2015-06-08

题目描述:求树中两个结点的最低公共祖先,此树不是二叉树,并且没有指向父节点的指针。

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import Foundation

public class MyTreeNode {
public var val: Int
public var children: [MyTreeNode]?
public init(_ val: Int) {
self.val = val
self.children = nil
}
}

class For50Solution {
func commonTreeNode(_ root: MyTreeNode,_ a: MyTreeNode,_ b: MyTreeNode) -> MyTreeNode? {

var list1 = [MyTreeNode]()
var list2 = [MyTreeNode]()
getNodePath(root, a, &list1)
getNodePath(root, b, &list2)

return getLastCommonNode(list1, list2)
}

func getNodePath(_ root: MyTreeNode?,_ p: MyTreeNode,_ list: inout [MyTreeNode]) {

if root!.val == p.val {
return
}

list.append(root!)

let arr = root!.children
if arr != nil {
for node in arr! {
if node.val == p.val {
list.append(node)
break
}

getNodePath(node, p, &list)
}
}

if list.last?.val != p.val {
list.removeLast()
}
}

func getLastCommonNode(_ p1: [MyTreeNode],_ p2: [MyTreeNode]) -> MyTreeNode? {

var temp: MyTreeNode? = nil
var index = 1

while index < p1.count {
if p1[index].val == p2[index].val {
temp = p1[index]
break
}
index += 1
}

return temp
}
}

算法思想:假设是二叉树做的。还要优化。

github地址:https://github.com/cubegao/LeetCode

Tags: 算法

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